2015
DOI: 10.1098/rspa.2015.0013
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Anisotropy and lack of symmetry for a random aggregate of frictionless, elastic particles: theory and numerical simulations

Abstract: International audienceWe consider a random aggregate of identical, frictionless spheres whose contact is maintained by an applied pressure. The aggregate is then subjected to an axial compression at fixed pressure. We show that the incremental elastic response of the resulting transversely isotropic material is characterized by six rather than by five independent coefficients and that the stiffness tensor does not have the major symmetry. This is because we permit deviations from an affine deformation that are… Show more

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Cited by 7 publications
(6 citation statements)
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“…We identify in this regime an inelastic stiffness in which the response becomes incrementally frictionless and the major symmetry of the macroscopic stiffness is lost (e.g. [20,21]). Key parameters are the magnitude and direction of the probes applied to stressed, anisotropic states, compared with the strain under which the aggregate is initially loaded.…”
Section: Introductionmentioning
confidence: 99%
“…We identify in this regime an inelastic stiffness in which the response becomes incrementally frictionless and the major symmetry of the macroscopic stiffness is lost (e.g. [20,21]). Key parameters are the magnitude and direction of the probes applied to stressed, anisotropic states, compared with the strain under which the aggregate is initially loaded.…”
Section: Introductionmentioning
confidence: 99%
“…As first shown by La Ragione et al (2015), the interaction of the fluctuations and the transverse anisotropy creates this property of , which is necessary for localization to occur. Numerical simulations are in progress and confirm the lack of symmetry for a frictional aggregate.…”
Section: Stiffness Tensormentioning
confidence: 93%
“…The six coefficients are with and As suggested by La Ragione et al [17,36], it is the presence of fluctuations in the kinematics of contacting particles that leads to 4 ≠ 5 which implies the loss of major symmetry for the anisotropic stiffness tensor A ijkm . It is the term proportional to 2 and the volume strain in Eq.…”
Section: Incremental Stressmentioning
confidence: 99%
“…[14]) is or, with Eq. (36) Given Eq. ( 37), we obtain The coefficients 's depend on the relation between the volume strain and the shear strain which are present in the contact stiffness K N .…”
Section: Second-order Workmentioning
confidence: 99%