1970
DOI: 10.2307/2036382
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Another Zero-Free Region for ζ (k) (s)

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1977
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Cited by 17 publications
(16 citation statements)
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“…In this paper we numerically investigate the distribution of zeros of the derivatives ζ (k) of ζ on the left half plane. The results of our computations, that considerably expands the list of previously published zeros [11,15], can be found in Table 1 and Table 2. For the rectangular region −10 < σ < 1 2 and |t| < 10, Table 1 contains the number of zeros of ζ (k) , its real zeros, and its zeros with 0 < σ < 1 2 .…”
Section: Introductionmentioning
confidence: 53%
See 2 more Smart Citations
“…In this paper we numerically investigate the distribution of zeros of the derivatives ζ (k) of ζ on the left half plane. The results of our computations, that considerably expands the list of previously published zeros [11,15], can be found in Table 1 and Table 2. For the rectangular region −10 < σ < 1 2 and |t| < 10, Table 1 contains the number of zeros of ζ (k) , its real zeros, and its zeros with 0 < σ < 1 2 .…”
Section: Introductionmentioning
confidence: 53%
“…For k ≥ 3 such general upper bounds were given by Spira [11] and later improved by Verma and Kaur [14]: where q 2 is given by the formula…”
Section: Zeros On the Right Half Planementioning
confidence: 99%
See 1 more Smart Citation
“…where n 1 , n 2 are integers, using (4) and applying an argument of R. Spira [4], we can prove that F (s) and F (s) − ζ(σ 0 + s) have the same number of zeros in the rectangle with vertices at M ± iT 0 , T ± iT 0 . Indeed, on the sides of this rectangle due to the Γ -factor we have Remark.…”
Section: F (S) Vanishes O(log T ) Times Between M + It and −M + Itmentioning
confidence: 99%
“…where the coefficients ajkm and bjkm are independent of s. This formula was used by Spira [11], [12] to determine zero-free regions for Ç(k)(s), and by Berndt [5], to determine the asymptotic number of zeros of £(fc)(s) with 0 < t < T, where s = a + it. This paper gives a variant of this formula (Theorem 1) which enables us to determine the coefficients ajkm and bjkm explicitly (Theorem 2).…”
Section: (-1) V*>(1 -S) = 2(2*r I E ( Wosf + Bjkmsmf)t^(s)^(s)mentioning
confidence: 99%