“…Consider two HFNs M ~ = ( m 1 , m 2 , m 3 , m 4 , m 5 , m 6 ) and N˜ = ( n 1 , n 2 , n 3 , n 4 , n 5 , n 6 ), then the operation on these two HFNs are as follows [ 50 ]: - Addition: M˜ ⊕ N˜ = ( m 1 + n 1 , m 2 + n 2 , m 3 + n 3 , m 4 + n 4 , m 5 + n 5 , m 6 + n 6 );
- Subtraction: M˜ − N˜ = ( m 1 − n 6 , m 2 − n 5 , m 3 − n 4 , m 4 − n 3 , m 5 − n 2 , m 6 − n 1 );
- Multiplication: M˜ × N˜ = ( m 1 × n 1 , m 2 × n 2 , m 3 × n 3 , m 4 × n 4 , m 5 × n 5 , m 6 × n 6 );
- Division: M˜/N˜ = ( m 1 / n 6 , m 2 / n 5 , m 3 / n 4 , m 4 / n 3 , m 5 / n 2 , m 6 / n 1 ).
- (b) The Distance between Two HFNs
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