2003
DOI: 10.1103/physrevb.67.104513
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Application of the theory of continuous media to the description of thermal excitations in superfluid helium

Abstract: We propose a model for the quasiparticles of superfluid 4 He which describes both phonons and rotons in a unified way. The theory is based on the fact that the thermal de Broglie wavelengths of the atoms overlap each other. This allows us to treat superfluid 4 He as a continuous medium at all length scales. Then the parameters of the continouous medium ͑density, pressure, and velocity͒ can be given a probabilistic value at each point in space. The quasiparticles of superfluid 4 He are small fluctuations in the… Show more

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Cited by 21 publications
(43 citation statements)
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“…This non-local relationship between pressure and density was used in the phenomenological approach of [35] (neglecting the quantum term) to describe the rotons in the superfluid helium. From our consideration, it follows that the non-locality kernel, which relates the pressure and the density in a phenomenological approach, is determined by the inter-particle interaction potential.…”
Section: Hydrodynamic Form Of Non-local Gross-pitaevskii Equationmentioning
confidence: 99%
“…This non-local relationship between pressure and density was used in the phenomenological approach of [35] (neglecting the quantum term) to describe the rotons in the superfluid helium. From our consideration, it follows that the non-locality kernel, which relates the pressure and the density in a phenomenological approach, is determined by the inter-particle interaction potential.…”
Section: Hydrodynamic Form Of Non-local Gross-pitaevskii Equationmentioning
confidence: 99%
“…We describe it with the help of the nonlocal hydrodynamics developed in [15]. According to it, in the infinite space the quantum fluid obeys the ordinary linearized equations of a continuous medium:…”
Section: Formulation Of the Problem Derivation Of Equations And Thementioning
confidence: 99%
“…In this form it does not contain a convolution product in the sense of the Fourier transform because of the finite lower limit. There is no convolution product in the sense of either the Laplace or one-sided Fourier transform because the function h x ( ) is even [15] and cannot become zero at x < 0. In order to solve equation (7) by the Fourier transform we have first to define the unknown function in the region x < 0 and to widen the limits of integration to infinity.…”
Section: Formulation Of the Problem Derivation Of Equations And Thementioning
confidence: 99%
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