2008
DOI: 10.1088/1742-6596/95/1/012002
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Asymptotics of Harish-Chandra-Itzykson-Zuber integrals and free probability theory

Abstract: Abstract.We discuss an asymptotic exponent N −1 log EA[exp(β tr X * AX/2)] in the limit N → ∞, where β = 1 or 2, where A is an N -by-N real symmetric (β = 1) or complex Hermitian (β = 2) random matrix, and where X is an N -by-M real (β = 1) or complex (β = 2) matrix, with M being kept finite while taking the limit N → ∞. Relation of the problem to the so-called Harish-Chandra or Itzykson-Zuber integrals are also discussed. Assuming that the result is given in terms of limiting eigenvalues of Q = N −1 X * X, we… Show more

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Cited by 12 publications
(11 citation statements)
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“…(B.4) is the Orthogonal low-rank version of the Harish-Chandra-Itzykson-Zuber integrals ( [44], [45]). The result is known for all symmetry groups ( [51], [52] or [53] for a more rigorous derivation), and reads for the rank-n case…”
Section: B Free Additive Noisementioning
confidence: 99%
“…(B.4) is the Orthogonal low-rank version of the Harish-Chandra-Itzykson-Zuber integrals ( [44], [45]). The result is known for all symmetry groups ( [51], [52] or [53] for a more rigorous derivation), and reads for the rank-n case…”
Section: B Free Additive Noisementioning
confidence: 99%
“…where • • • ρ denotes the average with respect to ρ(λ), while Extr θ {• • •} represents extremization with respect to θ [11]. This formula is analogous to the one known for ensembles of random square (symmetric) matrices [12], [13], [14], which is closely related to the R-transformation developed in free probability theory [15], [9], [16]. Several integral formulae for large random matrices related to Eq.…”
Section: A An Integral Formula For Large Random Rectangular Matricesmentioning
confidence: 94%
“…Recently, it has been shown in [11] that the same analyses can be obtained without the need of Gaussian distribution assumption but a sub-Gaussian tail condition of the distribution is required. Indeed, thanks to the central limit theorem, one can show that the generating function (3) also yields the same result regardless of whether the Gaussian distribution assumption is considered or not, see [23,Section 5].…”
Section: Example 2 the Hopfield Modelmentioning
confidence: 98%