2021
DOI: 10.48550/arxiv.2101.09245
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Bäcklund transformations: a tool to study Abelian and non-Abelian nonlinear evolution equations

Abstract: The KdV eigenfunction equation is considered: some explicit solutions are constructed. These, to the best of the authors' knowledge, new solutions represent an example of the powerfulness of the method devised. Specifically, Bäcklund transformation are applied to reveal algebraic properties enjoyed by nonlinear evolution equations they connect. Indeed, Bäcklund transformations, well known to represent a key tool in the study of nonlinear evolution equations, are shown to allow the construction of a net of nonl… Show more

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Cited by 1 publication
(3 citation statements)
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“…Note that the polynomial partial differential field includes even degree terms. Such alternative forms can be obtained from non-commutative modified Korteweg-De Vries equation via a suitable gauge transformation as, for example, outlined in detail in Carillo and Schiebold [23]. The combinatorial algebraic structure we have developed would seem a natural context to investigate such alternative hierarchy forms further.…”
Section: Discussionmentioning
confidence: 99%
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“…Note that the polynomial partial differential field includes even degree terms. Such alternative forms can be obtained from non-commutative modified Korteweg-De Vries equation via a suitable gauge transformation as, for example, outlined in detail in Carillo and Schiebold [23]. The combinatorial algebraic structure we have developed would seem a natural context to investigate such alternative hierarchy forms further.…”
Section: Discussionmentioning
confidence: 99%
“…If we follow the sub-diagonal with the view of retaining non-zero terms along it, we observe we meet a obstruction in the first 4 × 4 block with matrix A 2 characterised by the composition component 32. The problem is that while the sub-diagonal of A 2 has non-zero entries, the next term along the diagonal that lies in the last column of that A 2 block, but beneath the entire block, and in fact the row corresponding to the basis element [23] × (1, 0, 0, 0) is zero. However there is a quick fix to this obstruction.…”
Section: ⊓ ⊔mentioning
confidence: 99%
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