1997
DOI: 10.1007/3-540-63220-4_63
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Banishing bias from consensus sequences

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Cited by 54 publications
(37 citation statements)
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“…For general k, the problem of finding a string X such that max 1≤i≤k d(X, S i ) ≤ r is NP-hard even when characters in strings are drawn from the binary alphabet [4]. Thus, attention has been restricted to approximation solutions [2,5,6,[11][12][13][14] and fixed-parameter solutions [7,8,14,15].…”
Section: Problem 2 Bounded Consensusmentioning
confidence: 99%
“…For general k, the problem of finding a string X such that max 1≤i≤k d(X, S i ) ≤ r is NP-hard even when characters in strings are drawn from the binary alphabet [4]. Thus, attention has been restricted to approximation solutions [2,5,6,[11][12][13][14] and fixed-parameter solutions [7,8,14,15].…”
Section: Problem 2 Bounded Consensusmentioning
confidence: 99%
“…Finding similar regions in multiple DNA, RNA, or protein sequences plays an important role in many applications, including universal PCR primer design [4], [16], [18], [26], genetic probe design [16], antisense drug design [16], [3], finding transcription factor binding sites in genomic data [27], determining an unbiased consensus of a protein family [1], and motif-recognition [16], [24], [25]. The CLOSEST STRING problem formalizes these tasks and can be defined as follows: given a set of n strings S of length over the alphabet Σ and parameter d, the aim is determine if there exists a string s that has Hamming distance at most d from each string in S. We refer to s as the center string and let d(x, y) be the Hamming distance between strings x and y.…”
Section: Introductionmentioning
confidence: 99%
“…. , s n } of strings, say, each of length m. The Closest String problem [1,2,4,5,11] asks for the smallest d and a string s of length m which is within Hamming distance d to each s i ∈ S. This problem comes from coding theory when we are looking for a code not too far away from a given set of codes [4]. The problem is NP-hard [4,11].…”
Section: Introductionmentioning
confidence: 99%
“…Let d(s, s ′ ) denote the Hamming distance between s and s ′ . |s| is the length of s. s[i] is the i-th character of s. Thus, s = s [1]s [2] . .…”
Section: Introductionmentioning
confidence: 99%
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