2022
DOI: 10.1216/rmj.2022.52.1039
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Berezin number inequalities of operators on reproducing kernel Hilbert spaces

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Cited by 14 publications
(4 citation statements)
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“…Notably, we observe that ber(I Λ ) = 1 and Tk µ , k µ ≤ ber(T) k µ 2 hold for all reproducing kernels k µ . Similar to ber(T), we found in [11] the following concept:…”
Section: Introductionsupporting
confidence: 70%
See 1 more Smart Citation
“…Notably, we observe that ber(I Λ ) = 1 and Tk µ , k µ ≤ ber(T) k µ 2 hold for all reproducing kernels k µ . Similar to ber(T), we found in [11] the following concept:…”
Section: Introductionsupporting
confidence: 70%
“…From relation (1), we have the upper bound of T α,β as α T 2 + βω 2 (T), and from relation (11) the upper bound T 2 max α, β + αβ T ω(T). Comparing the two upper bounds, we find…”
Section: Resultsmentioning
confidence: 99%
“…It is clear from the definition that Ber(A) ⊆ W (A) and so ber(A) ≤ w(A). The Berezin symbols and Berezin number inequalities have been studied by many mathematicians over the years, for the latest and recent results we refer the readers to see [2,8,16,18,20,21,28,30] and the references therein.…”
Section: Introductionmentioning
confidence: 99%
“…Observe that the above equality may not be true for selfadjoint operators. The Berezin number and Berezin norm inequalities have been studied by many mathematicians [8,21,22,33,36,38,43,44].…”
Section: Introductionmentioning
confidence: 99%