2019
DOI: 10.1063/1.5063986
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Boundary triples for the Dirac operator with Coulomb-type spherically symmetric perturbations

Abstract: We determine explicitly a boundary triple for the Dirac operator H :Consequently we determine all the self-adjoint realizations of H in terms of the behaviour of the functions of their domain in the origin. When sup x |x||V(x)| ≤ 1, we discuss the problem of selecting the distinguished extension requiring that its domain is included in the domain of the appropriate quadratic form.

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Cited by 9 publications
(11 citation statements)
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“…a complete description of all the self-adjoint extensions is given in [6,5]. Under some conditions on the size of the constants ν, µ, λ, a distinguished extension is selected by means of a Hardy-type inequality and a quadratic form approach.…”
Section: Introduction and Main Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…a complete description of all the self-adjoint extensions is given in [6,5]. Under some conditions on the size of the constants ν, µ, λ, a distinguished extension is selected by means of a Hardy-type inequality and a quadratic form approach.…”
Section: Introduction and Main Resultsmentioning
confidence: 99%
“…Under some conditions on the size of the constants ν, µ, λ, a distinguished extension is selected by means of a Hardy-type inequality and a quadratic form approach. Nevertheless, in the particular case of the anomalous magnetic potential V(x) = ±iα • xβ|x| −1 such criteria do not appear to be strong enough to select any extension, see [6, Remark 1.10] and [5,Remark 1.6].…”
Section: Introduction and Main Resultsmentioning
confidence: 99%
“…2.5] and [CP18, Thms. 1.1 and 1.2], [CP19]. We provide it in full detail for convenience of the reader and also because we need to cover some additional aspects.…”
Section: Deficiency Indices and Self-adjoint Extensions For A Class O...mentioning
confidence: 99%
“…10) are true; thanks to (4.7),(4.11) holds for a large enough k.Condition (1.16) holds obviously for r ∈ [ρ k0 , ρ k1 ] ∪ [ρ k3 , ρ k4 ]. For the case r ∈ [ρ k1 , ρ k2 ] we need to distinguish various cases: let s := 4(r − ρ k1 )/(ρ k+1 − ρ k ) and let us consider first the case s ∈ (0, (log ρ k ) −3/2 ).…”
mentioning
confidence: 90%
“…In the massless case m = 0, ψ 0 is not in L 2 (R 3 ). We refer to [9,10] for a description of the functions in the domain of D 3 + V: we hope to investigate the phenomena described in this paper in the case that ǫ ≥ 1 in the future.…”
Section: Introductionmentioning
confidence: 99%