Abstract:A shift S : K 2 −→ K 2 on the double covering of the Klein bottle K 2 = K 2 × {±1} is considered. This shift S generates a tiling K 2 = K 2 0 K 2 1 by two bounded remainder sets K 2 0 and K 2 1 with respect to the shift S. Two-sided bounds for the deviation functions of these sets are proved. Bibliography: 16 titles. 0. Introduction 0.1. Bounded remainder sets. Let, on a compact manifold M, a mapping M S −→ M be given and letOrbbe the orbit of a certain initial point x 0 ∈ M with respect to the mapping S. For … Show more
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