2017
DOI: 10.1016/j.jpaa.2016.10.010
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Bounds for the exponent of the Schur multiplier

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Cited by 9 publications
(5 citation statements)
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“…The previous result improves the bounds obtained [1, 18, 24] (cf. [1, Theorem 6.5], [18, Section 2] and [24, Theorem 1.1]).…”
Section: The Exponent Of νFalse(gfalse)$\nu (G)$supporting
confidence: 88%
See 2 more Smart Citations
“…The previous result improves the bounds obtained [1, 18, 24] (cf. [1, Theorem 6.5], [18, Section 2] and [24, Theorem 1.1]).…”
Section: The Exponent Of νFalse(gfalse)$\nu (G)$supporting
confidence: 88%
“…In [18], Moravec showed that if G is a p ‐group of class c2$c\ge 2$, then expfalse(Mfalse(Gfalse)false)$\exp (M(G))$ divides expfalse(Gfalse)2log2(c)$\exp (G)^{2\lfloor \log _2(c)\rfloor }$. Later, in [24], Sambonet proved that if G is a p ‐group of class c2$c\ge 2$, then expfalse(Mfalse(Gfalse)false)$\exp (M(G))$ divides expfalse(Gfalse)logp1(c)+1$\exp (G)^{\big\lfloor \log _{p-1}(c)\big\rfloor +1}$ if p>2$p>2$ and expfalse(Mfalse(Gfalse)false)$\exp (M(G))$ divides 2log2(c)·expfalse(Gfalse)log2(c)+1$2^{\lfloor \log _2(c)\rfloor } \cdot \exp (G)^{\lfloor \log _2(c)\rfloor +1}$ if p=2$p=2$. In [1], Antony et al.…”
Section: Introductionmentioning
confidence: 99%
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“…Set m = ⌊log 2 (c)⌋ and d the derived length of G. According to Theorem 1.1 ii) and the formula d ≤ ⌊log 2 (c)⌋ + 1 (cf. [9, Theorem 5.1.12]), we deduce that exp(D(G)) divides 2 d−1 •exp(G) d and so, exp(D(G)) divides 2 m • exp(G) m+1 , which completes the proof.As an immediate consequence of the above result we obtain Sambonet's theorem[13, Theorem 1.1] concerning the exponent of the Schur multiplier of p-groups of class c. More precisely, we conclude the following extension.…”
supporting
confidence: 63%
“…More precisely, it is conjectured that exp M(G) divides exp G for a finite p-group p > 2. Confer [25] and the references therein. We show how there is at least a linear bound on the exponent of the Schur multiplier provided that the coclass is fixed.…”
Section: Theorem 42mentioning
confidence: 99%