2017
DOI: 10.1016/j.jalgebra.2016.09.021
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Brauer indecomposability of Scott modules

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Cited by 12 publications
(10 citation statements)
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“…g (∆P ) for some g ∈ G. It follows that∆R ≤ Ng (∆P ) (∆Q) ≤ N G (∆Q) N ∆P (∆Q)by Lemma 3.2 of[9]. Since N ∆P (∆Q) is a vertex of M 1 , we have that M 1 (∆R) ̸ = 0.…”
mentioning
confidence: 83%
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“…g (∆P ) for some g ∈ G. It follows that∆R ≤ Ng (∆P ) (∆Q) ≤ N G (∆Q) N ∆P (∆Q)by Lemma 3.2 of[9]. Since N ∆P (∆Q) is a vertex of M 1 , we have that M 1 (∆R) ̸ = 0.…”
mentioning
confidence: 83%
“…Since M (∆Q) is indecomposable as an N G (∆Q)-module, the fourth line of the proof of Theorem 1.3 in [9] implies that M (∆Q) = Sc(N G (∆Q), N ∆P (∆Q)), so that…”
Section: Lemma 24 Let G Be a Finite Group And Suppose Thatmentioning
confidence: 96%
“…Then G has a subgroup H such that t ∈ H ∼ = S 3 . Theorem 2.2 (Theorem 1.3 of [12]). Assume that P is a p-subgroup of G and F P (G) is saturated.…”
Section: Lemma 21 ([16 Lemma 42])mentioning
confidence: 99%
“…Hence, for a fixed i, a vertex of M i is contained in Nh ∆P (∆Q). Note that for such h, we have thatNh ∆P (∆Q) ≤ N H (∆Q) ∆Sby Lemma 3.2 of[9]. So for a fixed i, any vertex of M i is contained in ∆S.…”
mentioning
confidence: 91%