2011
DOI: 10.1016/j.cam.2011.02.019
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Calculating the edge Wiener and edge Szeged indices of graphs

Abstract: a b s t r a c tThe edge Szeged and edge Wiener indices of graphs are new topological indices presented very recently. It is not difficult to apply a modification of the well-known cut method to compute the edge Szeged and edge Wiener indices of hexagonal systems. The aim of this paper is to propose a method for computing these indices for general graphs under some additional assumptions.

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Cited by 51 publications
(22 citation statements)
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“…The authors apparently missed the whole series of papers that deal with computing distance based indices using the cut method. The same method was successively applied to hyper Wiener index [1], Szeged index [6], PI index [15], the edge-Wiener and edge-Szeged index [18], degree distance [7], weighted Wiener index [17], terminal Wiener index [8], etc. For some other applications and properties see [3], [4], [12], [13].…”
Section: Cut Methodsmentioning
confidence: 99%
“…The authors apparently missed the whole series of papers that deal with computing distance based indices using the cut method. The same method was successively applied to hyper Wiener index [1], Szeged index [6], PI index [15], the edge-Wiener and edge-Szeged index [18], degree distance [7], weighted Wiener index [17], terminal Wiener index [8], etc. For some other applications and properties see [3], [4], [12], [13].…”
Section: Cut Methodsmentioning
confidence: 99%
“…Corollary Let G be the circumcorone series benzenoid system H k , k ⩾ 1. W ( G ) = k (164 k 4 − 30 k 2 + 1)/5, W e ( G ) = 3 k (246 k 4 − 340 k 3 + 140 k 2 − 5 k − 1)/10, W e v ( G ) = k (492 k 4 − 340 k 3 + 25 k + 3)/10, S z v ( G ) = 3 k 2 (36 k 4 − k 2 + 1)/2, S z e ( G ) = k (1215 k 5 − 1599 k 4 + 680 k 3 − 105 k 2 + 55 k − 6)/10, S z e v ( G ) = k (1620 k 5 − 1066 k 4 + 135 k 3 − 10 k 2 + 45 k − 4)/20, S z t ( G ) = k (675 k 5 − 533 k 4 + 160 k 3 − 23 k 2 + 23 k − 2)/2, P I ( G ) = 81 k 4 − 68 k 3 + 12 k 2 − k , S ( G ) = 2 k (492 k 4 − 205 k 3 − 45 k 2 + 25 k + 3)/5, G u t ( G ) = k (1476 k 4 − 1230 k 3 + 230 k 2 + 75 k − 11)/5. …”
Section: Distance‐based Topological Indicesmentioning
confidence: 99%
“…Graph invariants constitute an interesting tool in Chemistry, Communication or Engineering [8,16,19]. In Mathematics, one of the topics for which graph invariants have revealed to play an important role is the classical problem of deciding whether two algebras are isomorphic.…”
Section: Introductionmentioning
confidence: 99%