1991
DOI: 10.1515/joc.1991.12.3.101
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CDMA Techniques in Optical Fiber LANs

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Cited by 4 publications
(3 citation statements)
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References 13 publications
(33 reference statements)
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“…An F 3 T interleaver is made up of three cascaded directional couplers as shown in with AL being the physical length difference of the differential delays that is associated with the phase of power spectrum 0. n is the refractive index, A the wavelength of the incident light signal, K, (i = 1, 2,3) is respectively the power coupling ratio of the i-th directional coupler that can be expressed in another form given by c* which is the bar-state coupling ratio and Sj is the cross-state coupling ratio. Note that P x3 (9) and Pu (9) are all periodical with respect to 0 or the incident wavelength A, and they satisfy Pn(0) + Pn(B) = 1 (6.36) which is usually referred to as the energy conservative condition.…”
Section: Design Problems Of F 3 T Interleaversmentioning
confidence: 99%
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“…An F 3 T interleaver is made up of three cascaded directional couplers as shown in with AL being the physical length difference of the differential delays that is associated with the phase of power spectrum 0. n is the refractive index, A the wavelength of the incident light signal, K, (i = 1, 2,3) is respectively the power coupling ratio of the i-th directional coupler that can be expressed in another form given by c* which is the bar-state coupling ratio and Sj is the cross-state coupling ratio. Note that P x3 (9) and Pu (9) are all periodical with respect to 0 or the incident wavelength A, and they satisfy Pn(0) + Pn(B) = 1 (6.36) which is usually referred to as the energy conservative condition.…”
Section: Design Problems Of F 3 T Interleaversmentioning
confidence: 99%
“…Given an unflatness level, the interleaver design problem is reduced to find those coupling ratios to maximize the channel isolation, that is, max{P 13 (0)-P 13 (7r/2)} (6.55) It is obvious that P\ 3 {92) = 1 and ^13(^3) = 1, which means P\ 3 (9) reaches its maximum at 9 = 0 2 and 9 = 9 3 . It is concluded in turn that P\ 3 {9) has a minimum at 9 = 0, otherwise Pu(&) would be flat over [^2,^3] because P\$ (9) has only three stationary points in [-TT/2,TT/2). Therefore, ^P > 0, which completes the proof that o > 0.…”
Section: Using ^ D6mentioning
confidence: 99%
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