“…Recently, motivated by a problem on p-blocks of p-solvable groups, a dual problem has come up (see [52]). As pointed out in the proof of Lemma 2.1 of [52], it is easy to see that if P is a p-group and A ≤ P is abelian, then χ(1) divides |P : A| for all χ ∈ Irr(P ). In particular, if |P | = p n and the exponent of P is p e , then χ(1) ≤ p n−e for every χ ∈ Irr(P ).…”