“…( ( 2 , 4 8 1 , (3,5,7,10,121, (6,91,11,1111 The corresponding partition on X is, with our preceding notations, It is of course possible to consider in the solution ( 5 ) the union of the two classes (7,10,12) and (3,5] and then that of the two classes 0 and @, replacing the Cartesian products (18) by ~~~~,~,~1 ,~~@~X 3 , 5 ,~,~0 ,~2 1 , @~~6 , 9 1 ,~…”