2004
DOI: 10.1090/s0002-9947-04-03622-0
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Classification of regular maps of negative prime Euler characteristic

Abstract: Abstract. We give a classification of all regular maps on nonorientable surfaces with a negative odd prime Euler characteristic (equivalently, on nonorientable surfaces of genus p + 2 where p is an odd prime). A consequence of our classification is that there are no regular maps on nonorientable surfaces of genus p + 2 where p is a prime such that p ≡ 1 (mod 12) and p = 13.

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Cited by 30 publications
(10 citation statements)
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“…(a) M has type (8,8) and G ∼ = C p ⋊ C 8 , of order 8p, with p ≡ 1 mod 8, (b) M has type (5,10) and G ∼ = C p ⋊ C 10 , of order 10p, with p ≡ 1 mod 10, (c) M has type (6,6) and G ∼ = C p ⋊ (C 6 × C 2 ), of order 12p, with p ≡ 1 mod 6.…”
Section: Preliminariesmentioning
confidence: 99%
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“…(a) M has type (8,8) and G ∼ = C p ⋊ C 8 , of order 8p, with p ≡ 1 mod 8, (b) M has type (5,10) and G ∼ = C p ⋊ C 10 , of order 10p, with p ≡ 1 mod 10, (c) M has type (6,6) and G ∼ = C p ⋊ (C 6 × C 2 ), of order 12p, with p ≡ 1 mod 6.…”
Section: Preliminariesmentioning
confidence: 99%
“…Now these include the eight pairs (3,15), (3,24), (3,42), (4,20), (6,12), (8,24), (9,18) and (12,12), with |G| = 2µ(k, ℓ)p = 20p, 16p, 14p, 10p, 8p, 6p, 6p and 6p, respectively, but as p ≥ 5, none of the listed group orders is divisible by the first entry k of the corresponding pair (k, ℓ), contradicting the fact that one generator of G has order k. Hence we can eliminate all of them from consideration. Also we can eliminate two further pairs, namely (7,42) and (5,20): in the former case, |G| = 2µ(k, ℓ)p = 6p and is divisible by ℓ = 42, and so p = 7, but then G ∼ = C 42 which is clearly not (7, 42, 2)-generated, while in the latter case |G| = 2µ(k, ℓ)p = 8p and is divisible by ℓ = 20, so p = 5, and then |G| = 40 and so G has a normal Sylow 5-subgroup P , but then the quotient G/P has order 8 and so is clearly not (1, 4, 2)-generated.…”
Section: Preliminariesmentioning
confidence: 99%
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