“…Likewise, a difference interval would be expected to require half as many observations (1791) before it did not contain zero. Using a ranking and selection procedure, we need to test n ϭ (1 Ϫ ␦* 2 )( s / 2␦*) 2 images from each system, where s is the number of systems being compared and s is a value tabulated by Gibbons, Olkin, and Sobel [4]. For the current case where s ϭ 2, 2 ϭ 2.3262 and thus n ϭ (1 Ϫ 0.03 2 )(2.3262/0.06) 2 ϭ 1502, providing some savings over both the confidence and difference interval techniques.…”