2019
DOI: 10.1002/jgt.22462
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Colourings of cubic graphs inducing isomorphic monochromatic subgraphs

Abstract: A k‐bisection of a bridgeless cubic graph G is a 2‐colouring of its vertex set such that the colour classes have the same cardinality and all connected components in the two subgraphs induced by the colour classes ( monochromatic components in what follows) have order at most k. Ban and Linial Conjectured that every bridgeless cubic graph admits a 2‐bisection except for the Petersen graph. A similar problem for the edge set of cubic graphs has been studied: Wormald conjectured that every cubic graph G wi… Show more

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Cited by 11 publications
(24 citation statements)
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“…Such properties assure that if we construct a flow f starting from f and by adding a flow equal to 1 k along every oriented cycle C i then we obtain a nowhere-zero (4 of S k . Indeed, the former property implies that the edge e has flow value k • 1 k = 1 in f , and the latter one implies that every other edge has flow value in the interval [1, 3 + 1 k ].…”
Section: Algorithm and Computational Resultsmentioning
confidence: 98%
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“…Such properties assure that if we construct a flow f starting from f and by adding a flow equal to 1 k along every oriented cycle C i then we obtain a nowhere-zero (4 of S k . Indeed, the former property implies that the edge e has flow value k • 1 k = 1 in f , and the latter one implies that every other edge has flow value in the interval [1, 3 + 1 k ].…”
Section: Algorithm and Computational Resultsmentioning
confidence: 98%
“…• For k ≥ 3, S k is obtained with a dot product of S k−1 and a copy of the Petersen graph where we select a pair of adjacent vertices of the Petersen graph (by symmetry every pair) and the two independent edges of S k as indicated in Figure 1 (bold edges). It is easy to check that S 2 has order 18 = 8 • 2 + 2 and that it has circular flow number 4 + 1 2 . Now, we assign to every S k an orientation as in Figure 1: the generalization to an arbitrary value of k is clear when we note that any new block with 8 vertices (obtained by dot product with a new copy of the Petersen graph) has the opposite orientation with respect to the last block in S k−1 .…”
Section: Algorithm and Computational Resultsmentioning
confidence: 99%
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“…Recently, we have given a detailed insight into Ban-Linial's Conjecture (as well as some other related conjectures) in [1], where we also presented theoretical and computational evidence for it. In particular, Ban-Linial's Conjecture is proven for bridgeless cubic graphs in the special case of cycle permutation graphs.…”
Section: Introductionmentioning
confidence: 98%