2010
DOI: 10.1109/tps.2010.2047274
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Compact 3-D Envelope ADI-FDTD Algorithm for Simulations of Coherent Radiation Sources

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Cited by 11 publications
(7 citation statements)
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“…The NEPTUNE code [1] has been created based on the new algorithm and used to explore its effectiveness for simulation. The code includes a model for the electron beam similar to that used in the NRL code TESLA, where an ensemble of macro-particles is distributed uniformly over both beam cross-section and entrance phase with respect to the RF field.…”
Section: Introductionmentioning
confidence: 99%
“…The NEPTUNE code [1] has been created based on the new algorithm and used to explore its effectiveness for simulation. The code includes a model for the electron beam similar to that used in the NRL code TESLA, where an ensemble of macro-particles is distributed uniformly over both beam cross-section and entrance phase with respect to the RF field.…”
Section: Introductionmentioning
confidence: 99%
“…However, the ADI-FDTD method is a split-step method while the conventional explicit FDTD method is a leapfrog method. Recently, the leapfrog ADI-FDTD method was introduced to better synchronize the conventional explicit FDTD and ADI-FDTD methods [28][29][30]. As is the case of the ADI-FDTD method, the leapfrog ADI-FDTD method retains the usage of the School of E. E. E Nanyang Technological University…”
Section: Domain Methodsmentioning
confidence: 99%
“…The leapfrog ADI-FDTD method uses the Yee's cells, and it has been derived from the conventional ADI-FDTD method [28][29][30]. As mentioned before, the conventional ADI-FDTD method is a split-step approach with two procedures.…”
Section: Leapfrog Adi-fdtd Methodsmentioning
confidence: 99%
“…Recently, a leapfrog ADI-FDTD method is further developed to enhance the computational efficiency with one-step update equation for the field components [24][25][26].…”
Section: Adi-fdtd Methodsmentioning
confidence: 99%
“…1 depicts the time-domain E z field component in the observation point(52,26,10) using explicit FDTD and FLOD-FDTD when CFLN=1, 4 and 8. The time step for explicit FDTD is set to the CFL limit ∆t CF L and CFLN is ∆t/∆t CF L .…”
mentioning
confidence: 99%