2019
DOI: 10.1103/physrevlett.123.040401
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Completely Positive Divisibility Does Not Mean Markovianity

Abstract: In the classical domain, it is well-known that divisibility does not imply that a stochastic process is Markovian. However, for quantum processes, divisibility is often considered to be synonymous with Markovianity. We show that completely positive (CP) divisible quantum processes can still involve non-Markovian temporal correlations, that we then fully classify using the recently developed process tensor formalism, which generalizes the theory of stochastic processes to the quantum domain.

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Cited by 117 publications
(100 citation statements)
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“…For the latter, it is also possible to quantify the violation of quantum regression theorem [58]. For the correspondence to classical Markovianity, a recent series of papers [55][56][57] exploited the concepts of process tensor and causal break. k ; A k−1:0 ).…”
mentioning
confidence: 99%
“…For the latter, it is also possible to quantify the violation of quantum regression theorem [58]. For the correspondence to classical Markovianity, a recent series of papers [55][56][57] exploited the concepts of process tensor and causal break. k ; A k−1:0 ).…”
mentioning
confidence: 99%
“…Memory effects are not an exclusive feature of quantum dynamics, being also present in classical physics. Our understanding regarding quantum non-Markovian behavior has markedly increased in the last few years [28][29][30]. Therefore, moving forward with this design, the question regarding the quantumness of the time-correlations generated in the output beam should be experimentally addressed by a measure of quantum non-Markovianity or by means of a Leggett-Garg inequality [31].…”
Section: Discussionmentioning
confidence: 99%
“…However, for n ≥ 4, Markovianity implies new kinds of monogamy constraints for the correlations in the Markov chain, violations of which can be seen as a device-independent test [20][21][22] of the non-Markovianity of the underlying process. Interestingly, arXiv:1910.04236v1 [quant-ph] 9 Oct 2019 by employing an operational definition of divisibility [23], we show that such condition is sufficient for a process satisfying all data processing and monogamy inequalities. Furthermore, we show how the violation of these new constraints can also be connected with the quantification of causal influences [16,24,25] among the variables.…”
Section: Introductionmentioning
confidence: 92%
“…If we also have access to p(Y, Z) then we can compute Γ Z:Y and check if Γ Z:X = Γ Z:Y Γ Y:X . The latter condition is stronger than the former because Γ Z:X represents the actual process Y → Z (see [23] for details).…”
Section: Inequalities For Divisible Processesmentioning
confidence: 99%
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