2014
DOI: 10.1090/s0002-9947-2014-06049-2
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Cone avoiding closed sets

Abstract: We prove that for an arbitrary subtree T of 2 <ω with each element extendable to a path, a given countable class M closed under disjoint union, and any set A, if none of the members of M strongly k-enumerate T for any k, then there exists an infinite set contained in either A orĀ such that for every C ∈ M, C ⊕ G also does not strongly k-enumerate T . We give applications of this result, which include: (1) RT 2 2 doesn't imply WWKL 0 ; (2) [Ambos-Spies et al. [1]] DNR is strictly weaker than WWKL 0 ; (3) ] for … Show more

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Cited by 30 publications
(49 citation statements)
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“…The result is interesting because it seems that the combinatorial argument in [8] relies heavily on the fact that A and A form a partition of ω.…”
Section: Introductionmentioning
confidence: 99%
“…The result is interesting because it seems that the combinatorial argument in [8] relies heavily on the fact that A and A form a partition of ω.…”
Section: Introductionmentioning
confidence: 99%
“…We can easily relate the notion of preservation of c.b-immunity with the existing notion of constant-bound enumeration avoidance defined by Liu [18] to separate RT 2 2 from WWKL over RCA 0 . Proof.…”
Section: Definition 9 (Constant-bound Immunity) a K-enumeration (K-ementioning
confidence: 99%
“…It can be seen as asserting the existence of a random real, in the sense of Martin-Löf [4]. Liu [10] introduced the notion of constant-bound enumeration avoidance to separate Ramsey's theorem for pairs from weak weak König's lemma. We shall use the same notion to separate CNS from WWKL.…”
Section: The Weakness Of Non-decreasing Subsequencesmentioning
confidence: 99%
“…Pick any x ∈ X. By iteratively applying strong c.b-enum avoidance of the infinite pigeonhole principle [10], define a finite sequence X = X 0 ⊇ X 1 ⊇ · · · ⊇ X k of infinite sets such that for each i < k, C has no X i+1 ⊕ C-computable c.b-enum and either there is some n < g i (x) such that g i (y) = n for each y ∈ X i+1 , or g i (y) ≥ g i (x) for each y ∈ X i+1 . If we are in the former case for some i < k, then the condition d = (F, X i+1 , S) is an extension of c such that #(d) < #(c).…”
Section: The Weakness Of Non-decreasing Subsequencesmentioning
confidence: 99%