2019
DOI: 10.1080/03081087.2019.1588849
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Constructing 2 × 2 × 4 and 4 × 4 unextendible product bases and positive-partial-transpose entangled states

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Cited by 16 publications
(6 citation statements)
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“…The studies of UPBs begin with the size of them [5]. Since then, the existence of UPBs with distinct sizes has received extensive attentions [13][14][15]. It is shown that all 4-qubit UPBs are constructed [16].…”
Section: Introductionmentioning
confidence: 99%
“…The studies of UPBs begin with the size of them [5]. Since then, the existence of UPBs with distinct sizes has received extensive attentions [13][14][15]. It is shown that all 4-qubit UPBs are constructed [16].…”
Section: Introductionmentioning
confidence: 99%
“…Hence, studying the six-dimensional CHM in terms of Schmidt rank connects the MUB problem and bipartite unitary operations. Besides, the technique employed in our results relate the MUB problem to other fundamental notions like multiqubit entangled states, unextendible product basis and Birkhoff matrices [23][24][25]. Very recently, bipartite operator of Schmidt rank three has been applied to the study of entanglement distillability of three bipartite reduced density operators from the same tripartite state [26].…”
Section: Introductionmentioning
confidence: 99%
“…Nonlocality is a fundamental feature of quantum mechanics [1,2]. It is also a key resource in information processing [3][4][5][6], and is related to various topics in quantum information theory such as the understanding of classical and quantum boundary [7,8], the entangling power of nonlocal unitary operations [9][10][11], and the efficient decomposition for realization in quantum circuits [12], unextendible product basis [13], and positivepartial-transpose entangled states [14].…”
Section: Introductionmentioning
confidence: 99%
“…Since S(Ψ abc ) = S(Ψ abd ) = S(Ψ acd ) = S(Ψ bcd ) ≤ 4 cos 2θ for the state Ψ abcd = |ψ abcd ψ abcd |, one gets the inequality(13).The equality holds in(13)when cos θ a cos θ c −cos θ a cos θ c = 2, ω = θ d = 0, θ d = π/2, namely, S max (Ψ abc ) = S max (Ψ abd ) = S max (Ψ acd ) = S max (Ψ bcd ) = 4 cos 2θ ≤ 4. It means that in this case all the reduced states of GGHZ state do not violate the Svetlichny inequality.…”
mentioning
confidence: 99%