2021
DOI: 10.1007/978-3-030-85088-3_2
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Continuants with Equal Values, a Combinatorial Approach

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Cited by 2 publications
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“…In fact, since Kn(x1,x2,,xn)=Kn(xn,,x2,x1)$K_n(x_1,x_2,\ldots ,x_n)=K_n(x_n,\ldots ,x_2,x_1)$, the reversal (or mirror image) of any extremal arrangement is again extremal. But more generally, the function Kfalse(·false)$K(\cdot )$ is far from being injective and it happens that many different permutations of the sequence y have the same K value [33]. There are many open questions concerning the distribution of the continuants Kn(x1,x2,,xn)$K_n(x_1,x_2,\ldots ,x_n)$ (ndouble-struckNfalse)$n\in \mathbb {N})$ where the xi$x_i$ are restricted to a bounded subset of positive integers, including the famous Zaremba conjecture [37].…”
Section: Introductionmentioning
confidence: 99%
“…In fact, since Kn(x1,x2,,xn)=Kn(xn,,x2,x1)$K_n(x_1,x_2,\ldots ,x_n)=K_n(x_n,\ldots ,x_2,x_1)$, the reversal (or mirror image) of any extremal arrangement is again extremal. But more generally, the function Kfalse(·false)$K(\cdot )$ is far from being injective and it happens that many different permutations of the sequence y have the same K value [33]. There are many open questions concerning the distribution of the continuants Kn(x1,x2,,xn)$K_n(x_1,x_2,\ldots ,x_n)$ (ndouble-struckNfalse)$n\in \mathbb {N})$ where the xi$x_i$ are restricted to a bounded subset of positive integers, including the famous Zaremba conjecture [37].…”
Section: Introductionmentioning
confidence: 99%
“…, x 2 , x 1 ), the reversal (or mirror image) of any extremal arrangement is again extremal. But more generally, the function K(•) is far from being injective and it happens that many different permutations of the sequence y have the same K value [33]. There are many open questions concerning the distribution of the continuants K n (x 1 , x 2 , .…”
Section: Introductionmentioning
confidence: 99%