“…According to eqn (2), the MAE of Ir 2 @TMD nanosheets was determined by the matrix elements of the spin–orbital interaction for the d electrons between occupied and unoccupied states. Because of the rotational symmetry of Ir 2 , the 5d orbits of Ir element are split into groups d xy / x 2 − y 2 , d xy / yz , and d z 2 , of which the non-zero matrix elements of the L z and L x operators 29,51,52 are xz | L z | yz = 1, x 2 − y 2 | L z | xz = 2, xy | L x | xz = 1, x 2 − y 2 | L x | yz = 1 and
, in units of ℏ. Then, the MAE can be obtained by analyzing the PDOS in a set energy range close to the Fermi energy, and can be expressed by the following formula:
where MAE uu , MAE dd , and MAE ud refer to the contributions provided by each pair of orbitals to the MAE in the main spin (uu), minority spin (dd), and cross-spin (ud) states, respectively.…”