2015
DOI: 10.1007/s11118-015-9493-2
|View full text |Cite
|
Sign up to set email alerts
|

Convolution of Probability Measures on Lie Groups and Homogenous Spaces

Abstract: We study (weakly) continuous convolution semigroups of probability measures on a Lie group G or a homogeneous space G/K, where K is a compact subgroup. We show that such a convolution semigroup is the convolution product of its initial measure and a continuous convolution semigroup with initial measure at the identity of G or the origin of G/K. We will also obtain an extension of Dani-McCrudden's result on embedding an infinitely divisible probability measure in a continuous convolution semigroup on a Lie grou… Show more

Help me understand this report

Search citation statements

Order By: Relevance

Paper Sections

Select...
3
1
1

Citation Types

0
5
0

Year Published

2016
2016
2024
2024

Publication Types

Select...
3
1
1

Relationship

0
5

Authors

Journals

citations
Cited by 5 publications
(5 citation statements)
references
References 13 publications
0
5
0
Order By: Relevance
“…Let M K (G) be the space of all right K-invariant Radon probability measures on G. We say that a continuous convolution semigroup (µ t , t ≥ 0) is right K-invariant, if µ t ∈ M K (G) for all t ≥ 0. In that case, µ 0 is normalised Haar measure on K, and then µ t is K-biinvariant for all t ≥ 0, as is shown in Proposition 2.1 of [20]. Indeed since for all t ≥ 0, µ t = µ 0 * µ t , left K-invariance of µ t follows from that of µ 0 .…”
Section: Restricted Convolution Semigroupsmentioning
confidence: 73%
See 3 more Smart Citations
“…Let M K (G) be the space of all right K-invariant Radon probability measures on G. We say that a continuous convolution semigroup (µ t , t ≥ 0) is right K-invariant, if µ t ∈ M K (G) for all t ≥ 0. In that case, µ 0 is normalised Haar measure on K, and then µ t is K-biinvariant for all t ≥ 0, as is shown in Proposition 2.1 of [20]. Indeed since for all t ≥ 0, µ t = µ 0 * µ t , left K-invariance of µ t follows from that of µ 0 .…”
Section: Restricted Convolution Semigroupsmentioning
confidence: 73%
“…So (µ t , t ≥ 0) is a continuous right K invariant convolution semigroup, with µ 0 being normalised Haar measure on K. Hence, by Proposition 2.1 of [20], µ t is K-bi-invariant for all t > 0.…”
Section: Restricted Convolution Semigroupsmentioning
confidence: 90%
See 2 more Smart Citations
“…It is shown in [26] that a convolution semigroup is K-left-invariant if and only if it is K-right-invariant if and only if it is K-bi-invariant. Then µ 0 = m K , (P t , t ≥ 0) as defined above 1 is a contraction semigroup on L 2 (K\G/K), and for each π ∈ G s , ( µ t (φ π ), t ≥ 0) is a strongly continuous one-parameter contraction semigroup of complex numbers.…”
Section: K-invariant Densities and Kernels For Convolution Semigroupsmentioning
confidence: 99%