1991
DOI: 10.1007/bf00383444
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Counting linear extensions

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Cited by 223 publications
(189 citation statements)
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“…Table 9 shows the number of monomials in the resulting polynomials for our random tests. Tables 10,12,11 show the test results of the three methods.…”
Section: 4mentioning
confidence: 99%
See 1 more Smart Citation
“…Table 9 shows the number of monomials in the resulting polynomials for our random tests. Tables 10,12,11 show the test results of the three methods.…”
Section: 4mentioning
confidence: 99%
“…It is very educational to look first at the case when f is the constant polynomial 1, and the answer is simply a volume. It has been proved that already computing the volume of polytopes of varying dimension is #P-hard [16,12,20,24], and that even approximating the volume is hard [17]. More recently in [28] it was proved that computing the centroid of a polytope is #P-hard.…”
Section: Introductionmentioning
confidence: 99%
“…The proof of Lemma 3 constructs a reduction from the #LinearExtension problem, whose #P-hardness has been established in [3].…”
Section: Lemmamentioning
confidence: 99%
“…Fix an instance of the #LinearExtension problem with input S and , and let ϑ be an approximation of Vol(P(S; )) to within an absolute accuracy of ∈ [0, 1/2k!). It is shown in [3] that the number of linear extensions N (S; ) of S under satisfies N (S; ) = k! Vol(P (S; )).…”
Section: #Linearextensionmentioning
confidence: 99%
“…Indeed, counting the number of predecessors of a sequence in the lattice is equivalent to counting the linear extensions of a partial order, which is #P-complete [16]. Furthermore, one needs to take into account the intersection of sets of predecessors, which makes the problem even more difficult.…”
Section: Conclusion and Further Research Directionsmentioning
confidence: 99%