“…However, in the cases with more than one figure (Cases 5,6,7,8,9,10,11,14,15,17,18,19,22 and 23), N, M and F are based on the first graph of the respective figures and P 1 , P 2 ,... denote the number of subgraphs of G which do not have the same configuration as the first graph but are counted in M. It is clear that F is equal to N × (M− P 1 −P 2 −...). To find N in each case, we have to include in any walk, all the edges and the vertices of the corresponding subgraphs at least once.…”