“…Let S,, = 5 ft (F A ) be the space of continuous functions which are linear in each triangle of T h with the usual modification for the curved éléments (see Ciarlet-Raviart [2], Zlamal [10]). The space S h is the intersection of S h and W\ 9 The approximation properties of the spaces S h and S h are wellknown; confer Ciarlet-Raviart [2] for example.…”
“…Let S,, = 5 ft (F A ) be the space of continuous functions which are linear in each triangle of T h with the usual modification for the curved éléments (see Ciarlet-Raviart [2], Zlamal [10]). The space S h is the intersection of S h and W\ 9 The approximation properties of the spaces S h and S h are wellknown; confer Ciarlet-Raviart [2] for example.…”
“…The uniqueness of solution to (1) and (2) indicates that the solution M £ has the représentation u^d-vl/Q)^!-^)" 1 /. (27) Take E = 0. The existence (1 -T ; ) -1 is seen as in [19] and we omit it In the proof of the following theorem we will see that T k+ie H-• T k , e -• 0.…”
Section: If Ve H^qir)) Is the Solution Of Avmentioning
confidence: 99%
“…[4], [23].) Near the boundary curved éléments are used [26], [27]. If S h dénotes the trial subspace of continuous piecewise linear functions (except over the curved triangles) which vanish on the nodes of the triangulation lying on the boundary of Q(R\ then the error estimate…”
Section: If Ve H^qir)) Is the Solution Of Avmentioning
“…We map K(t) on the (time independent) 406 L. CERMÂK, M. ZLÂMAL référence element K with vertices R t = (0, 0), R 2 = (1, 0), R 3 = (0, 1) in the £,, rj -plane. We have (see [7]) :…”
mentioning
confidence: 99%
“…We cover Q(0) by triangles completed along F(0) by curved éléments in a manner described in Zlâmal [7]. Let P k = (x h y k ), k = 1,..., d, be the nodes of this triangulation and let Q k = (a fc , (î fc ) be their inverse images in the mapping to 0)…”
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