“…Without loss of generality, assume that the graph G 1 is (α 1 , α 2 )-graph and the graph G 2 is (β 1 , β 2 )-graph. Since ∆(G) = 6, by attention to the structure of the graph B, with respect to the symmetry, the following cases for (α 1 α 2 , β 1 β 2 ) can be considered: (16,12), (15,12), (24,12), (14,12), (13,13). The graph G contains a copy of the complete bipartite graph K 1,6 , so the case (24,12) is not possible, also, the graph G contains a copy of complete bipartite graph K 3,6 , so the cases (16,12), (15,12), (14,12) are not possible.…”