2018
DOI: 10.1007/s40574-018-0169-x
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Del Pezzo surfaces, rigid line configurations and Hirzebruch–Kummer coverings

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Cited by 2 publications
(8 citation statements)
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“…The orbit of s 21 inside M ′ for the subgroup generated by 3 and ∶= (1, 2, 3)(4, 5) has at least 7 elements, hence it equals M ′ . Since (3,4) sends s 21 to − 32 , follows that M is a single 5 -orbit. Hence the stabilizer of s 21 has cardinality 5: but we know that it contains (1,2,3,4,5).…”
Section: Remark 32mentioning
confidence: 98%
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“…The orbit of s 21 inside M ′ for the subgroup generated by 3 and ∶= (1, 2, 3)(4, 5) has at least 7 elements, hence it equals M ′ . Since (3,4) sends s 21 to − 32 , follows that M is a single 5 -orbit. Hence the stabilizer of s 21 has cardinality 5: but we know that it contains (1,2,3,4,5).…”
Section: Remark 32mentioning
confidence: 98%
“…Proof The bijection follows immediately from the fact that we have two transitive actions, and the stabilizer of s 21 is the cyclic subgroup generated by (1,2,3,4,5), which is also the stabilizer of the standard pentagon corresponding to the identity map. We define then (m) by the property that it associates to an oriented pentagon p(i) the neighbouring oriented pentagon p(2i); from this definition follows that 2 4 ◻…”
Section: Definingmentioning
confidence: 98%
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