2006
DOI: 10.1007/s10659-005-9038-9
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Derivatives of the Stretch, Rotation and Exponential Tensors in n-Dimensional Vector Spaces

Abstract: We present a solution for the tensor equation TX + XT T = H, where T is a diagonalizable (in particular, symmetric) tensor, which is valid for any arbitrary underlying vector space dimension n. This solution is then used to derive compact expressions for the derivatives of the stretch and rotation tensors, which in turn are used to derive expressions for the material time derivatives of these tensors. Some existing expressions for n = 2 and n = 3 are shown to follow from the presented solution as special cases… Show more

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Cited by 16 publications
(17 citation statements)
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“…where we define the fourth-order identity tensor as I = I I and the square tensor product by (A B) C = ACB T for any second-order tensors A, B, C. We invert [26] the fourth-order tensor [µ 1 I + µ 2 I M ⊗ M + µ 2 M ⊗ M I] and multiply the inverse on both the sides of (85) to express B 0 as a function of τ and M :…”
Section: Discussionmentioning
confidence: 99%
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“…where we define the fourth-order identity tensor as I = I I and the square tensor product by (A B) C = ACB T for any second-order tensors A, B, C. We invert [26] the fourth-order tensor [µ 1 I + µ 2 I M ⊗ M + µ 2 M ⊗ M I] and multiply the inverse on both the sides of (85) to express B 0 as a function of τ and M :…”
Section: Discussionmentioning
confidence: 99%
“…by inverting a fourth order tensor [26] and the non-linear constitutive relation for transversely isotropic materials. The expression of initial strain obtained in terms of stress and texture is given by…”
Section: Constitutive Models For Initial Stress and Texture-induced A...mentioning
confidence: 99%
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“…AX + XA = C is an important and common equation in mechanics [13,11]. The solution may be written simply and succinctly as X = (A⊠I + I⊠A) −1 C where [8] (eq. ( 22)) (A⊠I + I⊠A) −1 = d i,j=1…”
Section: 14d)mentioning
confidence: 99%
“…It also has the same eigenvalues as the (symmetric) tensor in the square parenthesis, and since the eigenvalues of a symmetric tensor are real, the eigenvalues of T are real. Using these results, the procedure in [30] can now be used to compute both e T and *e T /*T.…”
mentioning
confidence: 99%