“…Th% Pp is then { 1, a, a ,a } and from Equation (6) the GTB to the PB is { 1, a , a , a} with = a . Hence if (ao,, al, a2, a3) is the PB representation of a E GF( 2 ) , the GTB of this element is (ao, a3, a2, a l ) which is a simple permutation of the PB coefficients.…”