2021
DOI: 10.46298/dmtcs.6108
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Destroying Bicolored $P_3$s by Deleting Few Edges

Abstract: We introduce and study the Bicolored $P_3$ Deletion problem defined as follows. The input is a graph $G=(V,E)$ where the edge set $E$ is partitioned into a set $E_r$ of red edges and a set $E_b$ of blue edges. The question is whether we can delete at most $k$ edges such that $G$ does not contain a bicolored $P_3$ as an induced subgraph. Here, a bicolored $P_3$ is a path on three vertices with one blue and one red edge. We show that Bicolored $P_3$ Deletion is NP-hard and cannot be solved in $2^{o(|V|+|E|)}$ ti… Show more

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Cited by 3 publications
(16 citation statements)
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“…We first prove the NP-hardness of cP ℓ D and cC ℓ D. In our analysis we focus on the impact of cascading effects on the complexity: The NP-hardness of 2P 3 D relies on the fact that edge deletions may create new bicolored P 3 s, as 2P 3 D is polynomial-time solvable on graphs that do not provide this cascading effect [17]. Here, we show that cP ℓ D with ℓ ≥ 4 and c ∈ [2, ℓ − 2] is NP-hard even when limited to instances where G is non-cascading, defined as follows.…”
Section: Classical Complexitymentioning
confidence: 99%
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“…We first prove the NP-hardness of cP ℓ D and cC ℓ D. In our analysis we focus on the impact of cascading effects on the complexity: The NP-hardness of 2P 3 D relies on the fact that edge deletions may create new bicolored P 3 s, as 2P 3 D is polynomial-time solvable on graphs that do not provide this cascading effect [17]. Here, we show that cP ℓ D with ℓ ≥ 4 and c ∈ [2, ℓ − 2] is NP-hard even when limited to instances where G is non-cascading, defined as follows.…”
Section: Classical Complexitymentioning
confidence: 99%
“…Proof. We prove this theorem by giving a polynomial time reduction from the NP-hard 2P 3 D problem [17].…”
Section: C-colored P ℓ Deletionmentioning
confidence: 99%
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