1976
DOI: 10.1016/0011-2275(76)90001-1
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Determination of vortex friction in a rotating type ii superconductor with a self-compensating torsion balance

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Cited by 30 publications
(9 citation statements)
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“…In the first (initial) region, the sample does not respond to the increase in ω ω = one could find similarly to [24,25] the expression for the total braking torque τ [19]. If in this region the torsion head is stopped, then at the expense of relaxation processes connected with the presence of viscous forces acting on vortex filaments, the sample will continue the rotation in the same direction (with decreasing velocity) until it reaches a certain equilibrium position, depending on the value.…”
Section: Resultssupporting
confidence: 58%
“…In the first (initial) region, the sample does not respond to the increase in ω ω = one could find similarly to [24,25] the expression for the total braking torque τ [19]. If in this region the torsion head is stopped, then at the expense of relaxation processes connected with the presence of viscous forces acting on vortex filaments, the sample will continue the rotation in the same direction (with decreasing velocity) until it reaches a certain equilibrium position, depending on the value.…”
Section: Resultssupporting
confidence: 58%
“…Torque measurements on conventional superconductors [5][6][7] were made in connection with an investigation of magnetic flux pinning by crystal lattice inhomogeneities. Since the discovery of high-temperature superconductivity (HTSC) and the observation of the orientation of fine particles of these anisotropic compounds in a magnetic field [8][9][10], the possibility of intrinsic torque in anisotropic superconductors in the region of equilibrium magnetization has been assumed [11].…”
Section: Introductionmentioning
confidence: 99%
“…Just in this region, when ω 1 = ω 2 the torque τ , appeared to the uniformly rotating sample, is balanced by the countermoment τ p and τ fr . In particular, in the case of a continuously rotating sample with frequency ω 1 = ω 2 one could find similarly to [26,27] the expression for the total braking torque τ [19].…”
Section: Resultsmentioning
confidence: 79%