2019
DOI: 10.24000/0409-2961-2019-12-60-65
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Development of the Activities for Explosive Gases Removal from the Worked-out Area in Case of Potash Mine Flooding

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Cited by 3 publications
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“…To estimate the duration of the process of removing the gas-air mixture from the worked-out area, as well as to calculate the change in the content of explosive gases in the outgoing stream, a new mathematical model of the degassing process was developed. The basis of this model is the degassing model proposed in [23]. However, we have supplemented it with an empirical time dependence of the volume of flammable gases released, taking into account the altitude of the incoming brine level.…”
Section: Methodsmentioning
confidence: 99%
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“…To estimate the duration of the process of removing the gas-air mixture from the worked-out area, as well as to calculate the change in the content of explosive gases in the outgoing stream, a new mathematical model of the degassing process was developed. The basis of this model is the degassing model proposed in [23]. However, we have supplemented it with an empirical time dependence of the volume of flammable gases released, taking into account the altitude of the incoming brine level.…”
Section: Methodsmentioning
confidence: 99%
“…In [23], it was demonstrated that the air resistance of the degassing pipeline and the 'back pressure' of the gas-air mixture in the closed section of the mine do not significantly affect the time it takes to fill the worked-out space with brine. Therefore, the current volume of the unfilled section is linearly dependent on time 𝑡:…”
Section: Methodsmentioning
confidence: 99%
“…where 𝛼 = 0.002 kg/m 3 is the aerodynamic drag coefficient of the degassing pipeline, the value of which is calculated using the method described in [24]; 𝐿 = 3900 m is the length of the degassing pipeline; 𝑆 is the cross-sectional area of the degassing pipeline, m 2 ; 𝛱 is the cross-section perimeter of the degassing pipeline, m. In [23], it was demonstrated that the air resistance of the degassing pipeline and the 'back pressure' of the gas-air mixture in the closed section of the mine do not significantly affect the time it takes to fill the worked-out space with brine. Therefore, the current volume of the unfilled section is linearly dependent on time 𝑡: 𝑉 = 𝑉 − 𝑞𝑡.…”
Section: Methodsmentioning
confidence: 99%