“…(33)Denotec 1 = (2C 1 ) −β/α . Then {(ω,τ): ρ(ω,τ)≥(|y−z|/2C 1 ) 1/α } ρ(ω, τ) −β dµ(ω) dµ(τ) = c 1 |y−z| −β/α µ × µ) (ω, τ) : ρ(ω, τ) ≤ t −1/β dt ≤ c 1 |y−z| −β/α −γ µ /β dt |y − z| − β−γµ α (recall that γ µ < β),where we used(23). Finally,R 2d |y − z| − β−γµ α dη(y) dη(z) < ∞,in view of(26), and so I 2 r d by(33), as desired.…”