2016
DOI: 10.1515/ms-2015-0157
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Diophantine equation X 4+Y 4 = 2(U 4 + V 4)

Abstract: Abstract. In this paper, the theory of elliptic curves is used for finding the solutions of the quartic Diophantine equation X 4 + Y 4 = 2(U 4 + V 4 ).

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Cited by 6 publications
(10 citation statements)
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“…This is the same DE (1) given in the Introduction for k = 6A 2 , that has been studied by some authors (see [1][2][3][4][5][6]). Then we may solve the DE (1) for all of the values k = 6A 2 , which rank of the elliptic curve (11) is positive.…”
Section: Now We Work Out Some Examplesmentioning
confidence: 54%
See 1 more Smart Citation
“…This is the same DE (1) given in the Introduction for k = 6A 2 , that has been studied by some authors (see [1][2][3][4][5][6]). Then we may solve the DE (1) for all of the values k = 6A 2 , which rank of the elliptic curve (11) is positive.…”
Section: Now We Work Out Some Examplesmentioning
confidence: 54%
“…has already been studied by some authors. Four cases k = 1, k = 6r + 1, k = −8, and k = 2n 2 , where n is a congruent number, has been studied in [1][2][3][4][5][6].…”
Section: Introductionmentioning
confidence: 99%
“…We use the fact that T (Q) is infinite to deduce that infinitely many specializations of E have the rank at least 5 over Q. This is done by using some elliptic curves of positive rank lying on T that we found in [8,9].…”
Section: Previous Workmentioning
confidence: 99%
“…In [8] Izadi and Nabardi found infinitely many integer solutions of this equation. Their method is based on the points of the elliptic curve y 2 = x 3 − 36x with a generator (−3, 9) explained as follows: Let P n = (x n , y n ), where P n = n · (−3, 9) (n ∈ N) is a point on the elliptic curve y 2 = x 3 − 36x, one gets A n = φ n 4 + 1296ψ n 8 + 864φ n ψ n 6 + 72φ n 2 ψ n 4 + 144ω n ψ n 5 −24φ n 3 ψ n 2 + 4φ n 2 ω n ψ n , D n = −864φ n ψ n 6 − φ n 4 − 1296ψ n 8 − 72φ n 2 ψ n 4 + 144ω n ψ n 5 +24φ n 3 ψ n 2 + 4φ n 2 ω n ψ n , B n = 4(φ n 2 + 36ψ n 4 )ω n ψ n ,…”
Section: Finding the Solutions Of The Equationmentioning
confidence: 99%
“…has already been studied by some authors. Four cases k = 1, k = 6r + 1, k = −8, and k = 2n 2 , where n is a congruent number, has been studied in [1][2][3][4][5][6].…”
Section: Introductionmentioning
confidence: 99%