2000
DOI: 10.1007/978-1-4612-1210-2
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Diophantine Geometry

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Cited by 410 publications
(370 citation statements)
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“…We shortly explain how this result is deduced from Proposition 6·1. If f (x, y) = 0 then there exists an absolutely irreducible factor g(X, Y ) of f , which then fulfils the conditions of Proposition 6·1, thus we may apply that for g. Further, since g divides f it is also well known that h(g) ≤ h(f ) + 2N (see Proposition B.7.3 of [19]). …”
Section: ·1 the Results For The Number Field Casementioning
confidence: 94%
“…We shortly explain how this result is deduced from Proposition 6·1. If f (x, y) = 0 then there exists an absolutely irreducible factor g(X, Y ) of f , which then fulfils the conditions of Proposition 6·1, thus we may apply that for g. Further, since g divides f it is also well known that h(g) ≤ h(f ) + 2N (see Proposition B.7.3 of [19]). …”
Section: ·1 the Results For The Number Field Casementioning
confidence: 94%
“…Proposition 8. 8. Let X be an irreducible variety of dimension n, L an ample line bundle on X, and x ∈ X(k).…”
Section: David Mckinnon and Mike Rothmentioning
confidence: 99%
“…Note that for x ∈ C(K) (5.1) ||j a (x)|| 2 Θ = gh a (x) + O( 1 + h a (x)) (this follows from [HS,Theorem B.5.9], since j * a Θ is algebraically equivalent to g · (a); cf. [HS,Theorem A.8.2.1]).…”
Section: Rational Points: Beyond 2/dmentioning
confidence: 99%
“…Note that for x ∈ C(K) (5.1) ||j a (x)|| 2 Θ = gh a (x) + O( 1 + h a (x)) (this follows from [HS,Theorem B.5.9], since j * a Θ is algebraically equivalent to g · (a); cf. [HS,Theorem A.8.2.1]). By the proof of Mumford's gap principle (see [HS,Theorems A.8.2.1 and B.6.5]), one has, for any x, y ∈ C(K), Now suppose that x, y ∈ C(K) are chosen so that h a (x), h a (y) ≤ h 0 .…”
Section: Rational Points: Beyond 2/dmentioning
confidence: 99%
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