“…2 (x, y) = 1 (x) 1 (y) and 2 (x, y) = 1 (x) 1 (y) for all x, y V. (1) and (3) we get 2 (x, y) = 2 (x, y) (4) If 1 normal, 1 (t) =1 for some t. Then (2) and (5) we get 2 (x, y) = 2 (x, y) (6) Now assuming that 2 k (x, y) = 2 (x, y) and 2 k (x, y) = 2 (x, y) we will prove 2 k+1 (x, y) = 2 (x, y) and 2 k+1 (x, y) = 2 (x, y) we have (u) 11 (v) (iv) from (iii) and (iv) we get (i) ( 12 + 22 )(u,v)= 12 (u,v) (v) and ( 11 + 21 )(u) ( 11 + 21 )(v)= 11 (u) 11 (v) (vi) from (v) and (vi) we get (ii) Therefore we get G 1 + G 2 is a product intuitionistic fuzzy sub graph of G. Similarly we can prove (u, v) X 1 . (u) 11 (v) and 12 (u, v) = 11 (u) 11 (v).…”