2016
DOI: 10.1103/physreve.94.032133
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Dynamical phase transition in large-deviation statistics of the Kardar-Parisi-Zhang equation

Abstract: We study the short-time behavior of the probability distribution P(H, t) of the surface height h(x = 0, t) = H in the Kardar-Parisi-Zhang (KPZ) equation in 1 + 1 dimension. The process starts from a stationary interface: h(x, t = 0) is given by a realization of two-sided Brownian motion constrained by h(0, 0) = 0. We find a singularity of the large deviation function of H at a critical value H = Hc. The singularity has the character of a second-order phase transition. It reflects spontaneous breaking of the re… Show more

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Cited by 67 publications
(249 citation statements)
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References 63 publications
(115 reference statements)
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“…A new feature arises at the value H = H c2 (w) where the validity of the first analytic continuations ends. We obtain H c2 (0) ≈ 1.85316 consistent with the numerical estimate of [24], which suggests that this is the same critical point. We propose two continuations for Φ(H) for H > H c2 (w), given in (30), an analytic one which leads to c + = 4/3, apparently corresponding to the symmetric WNT solution and a non-analytic one which leads to c + = 2/3, corresponding to the asymmetric WNT solution.…”
supporting
confidence: 85%
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“…A new feature arises at the value H = H c2 (w) where the validity of the first analytic continuations ends. We obtain H c2 (0) ≈ 1.85316 consistent with the numerical estimate of [24], which suggests that this is the same critical point. We propose two continuations for Φ(H) for H > H c2 (w), given in (30), an analytic one which leads to c + = 4/3, apparently corresponding to the symmetric WNT solution and a non-analytic one which leads to c + = 2/3, corresponding to the asymmetric WNT solution.…”
supporting
confidence: 85%
“…A surprising feature arises on the positive H side, where for H > H c2 a spontaneous symmetry breaking of reflection invariance occurs, leading to the coexistence of symmetric and asymmetric solutions. The value H c2 ≈ 1.85 was obtained numerically in [24]. While the symmetric solution gives c + = 4/3 the asymmetric ones gives c + = 2/3, i.e.…”
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confidence: 85%
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