2005
DOI: 10.1016/j.jct.2005.01.006
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Effect of pressure on melting temperature of carbon dioxide

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Cited by 3 publications
(2 citation statements)
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“…(6) are as follows: Tm = 2327 K [18], Hm = 21.76 KJ g-atom -1 [19],Sm=Hm/Tm=9.35Jg-atom -1 K -1, Sm=Sel+Spos+Svib, Sel is negligibly small, and Spos=-R[xAln(xA)+ xVln(xV)], where xA= 1/(1+ΔVm) and xV=ΔVm /(1+ΔVm) are the molar fractions of the host material and vacancies, respectively [20], and ΔVm is the volume difference between the crystal and corresponding fluid at Tm. As result, Svib= Sm-Spos or Svib  Sm+ R[xAln(xA)+ xVln(xV)] [21]. ΔVm=(VL-VS)/VS, Svib=5.6 Jg-atom -1 K -1 , h = 0.191 nm [18],  = 0.690 Jm -2 , S =3.86×10-12 Pa -1 is determined by  =1/B with B =289.55 GPa being the bulk modulus [21], VS = 5.14 cm3 g-atom [21], VL = 6.16 cm 3 g-atom -1 [18], L =57.9×10-12 Pa -1 as a first-order approximation under higher pressure, we assume L  15S [13].…”
Section: Resultsmentioning
confidence: 99%
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“…(6) are as follows: Tm = 2327 K [18], Hm = 21.76 KJ g-atom -1 [19],Sm=Hm/Tm=9.35Jg-atom -1 K -1, Sm=Sel+Spos+Svib, Sel is negligibly small, and Spos=-R[xAln(xA)+ xVln(xV)], where xA= 1/(1+ΔVm) and xV=ΔVm /(1+ΔVm) are the molar fractions of the host material and vacancies, respectively [20], and ΔVm is the volume difference between the crystal and corresponding fluid at Tm. As result, Svib= Sm-Spos or Svib  Sm+ R[xAln(xA)+ xVln(xV)] [21]. ΔVm=(VL-VS)/VS, Svib=5.6 Jg-atom -1 K -1 , h = 0.191 nm [18],  = 0.690 Jm -2 , S =3.86×10-12 Pa -1 is determined by  =1/B with B =289.55 GPa being the bulk modulus [21], VS = 5.14 cm3 g-atom [21], VL = 6.16 cm 3 g-atom -1 [18], L =57.9×10-12 Pa -1 as a first-order approximation under higher pressure, we assume L  15S [13].…”
Section: Resultsmentioning
confidence: 99%
“…As result, Svib= Sm-Spos or Svib  Sm+ R[xAln(xA)+ xVln(xV)] [21]. ΔVm=(VL-VS)/VS, Svib=5.6 Jg-atom -1 K -1 , h = 0.191 nm [18],  = 0.690 Jm -2 , S =3.86×10-12 Pa -1 is determined by  =1/B with B =289.55 GPa being the bulk modulus [21], VS = 5.14 cm3 g-atom [21], VL = 6.16 cm 3 g-atom -1 [18], L =57.9×10-12 Pa -1 as a first-order approximation under higher pressure, we assume L  15S [13]. f is calculated through Eq.…”
Section: Resultsmentioning
confidence: 99%