“…The wave functions calculated on the basis of the α + α + n model [2][3][4][5], which take this circumstance into account, describe well the static properties of the 9 Ве nucleus; electromagnetic form factors; and observables of elastic π 9 Ве, K 9 Ве, and p 9 Ве scattering [2][3][4][5][6][7][8][9]. The 9 Ве nucleus is a Borromean nucleus, since, within the α + α + n three-particle picture, there are no two components that could form a bound system (the same is true for 6 He in the α + n + n channel and for 11 Li in the 9 Li + n + n channel). The value of the ground-state root-mean-square radius of this nucleus ( r 2 1/2 = 2.45(1) fm) [1] is not indicative of the presence of a halo structure in it, but, in its first excited state, whose spin-parity and energy are J π = 1/2 + and E * = 1.68 MeV, respectively, the rootmean-square radius is larger ( r 2 1/2 = 2.83 fm).…”