The synthesis of stannole anions bearing various substituents on the tin atom is described. The reduction of hexaphenylstannole by the proper amount of lithium gave 1,2,3,4,5‐pentaphenylstannole anion 1. The reaction of 1 with 1,n‐dihaloalkanes (n = 1, 3, 4, 5, 6) gave the corresponding 1,n‐bis(1‐stannacyclopentadien‐1‐yl)alkanes. In contrast, the reaction of 1 with 1,2‐dihaloalkanes gave the 1,1′‐bistannole. The reactions of stannole dianion 3 with an equimolar amount of bulky alkyl, aryl, silyl, and stannyl halides gave the corresponding stannole anions. (© Wiley‐VCH Verlag GmbH & Co. KGaA, 69451 Weinheim, Germany, 2007)