1958
DOI: 10.1103/revmodphys.30.482
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Electromagnetic Structure of the Proton and Neutron

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Cited by 204 publications
(74 citation statements)
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“…In such fit, two solutions appear also for G m , related to the choice of the other two FFs. 1 The value for Gq corresponding to Q = 2.788 fm −1 should be 2.59 +0.07 −0.71 , instead of 2.59(±0.073) [20] …”
Section: Resultsmentioning
confidence: 99%
See 1 more Smart Citation
“…In such fit, two solutions appear also for G m , related to the choice of the other two FFs. 1 The value for Gq corresponding to Q = 2.788 fm −1 should be 2.59 +0.07 −0.71 , instead of 2.59(±0.073) [20] …”
Section: Resultsmentioning
confidence: 99%
“…Since the pioneering work of Hofstadter [1], a large number of experimental data have been collected about hadron electromagnetic FFs, especially in the space-like region. It is important to note that a relatively simple phenomenological parametrizations can be found for the description of the Q 2 dependence of different FFs, despite the possible complicated dynamics which determines the hadronic electromagnetic structure.…”
Section: Introductionmentioning
confidence: 99%
“…These FFs were then introduced in experimental papers by Hofstadter and coworkers [Hof56,McA56,Hof58], who generalized the "effective" charge and magnetic moment concepts by associating the first with the deviation from a point charge Dirac particle (Dirac FF, F 1 ), and the second with the deviation from a point anomalous magnetic moment (Pauli FF, F 2 ).…”
Section: The Dirac and Pauli Nucleon Form Factorsmentioning
confidence: 99%
“…Experiments aimed at studying the proton form factors (FFs), the electric (G E ) and magnetic (G M ) ones, which are frequently referred to as the Sachs FFs, have been performed since the mid 1950 s [1,2] by using elastic electron-proton scattering. In the case of unpolarized electrons and protons, all experimental data on the behavior of the proton FFs were obtained by using the Rosenbluth formula [1] for the differential cross section for the reaction ep → ep; that is, dσ dΩ e = α 2 E 2 cos 2 (θ e /2) 4E 3 1 sin 4 (θ e /2)…”
Section: Introductionmentioning
confidence: 99%