“…Therefore, β − β n = O p (n − 1 2 ) which implies β = β n + n − 1 2 u with |u| < +∞. Since ψ j (I(ω j ), β n ) → ψ j (I(ω j ), β) in probability, from Monti (1997) we have, 1 n n j=1 ψ j ψ j = 1 n n j=1 ψ j (I(ω j ), β n )ψ j (I(ω j ), β n ) + O p (n − 1 2 ) =Σ(β n ) + O p (n − 1 2 ), (A.5) whereΣ (β n ) = 1 n n j=1 ψ j (I(ω j ), β n )ψ j (I(ω j ), β n ) .…”