“…from(35) and the second equation in(29) from(36)we obtain e (n+1/2) v,S,∆t = e (n−1/2) v,S,∆t − (∆t) A S,p e Eliminating the term e (n+1/2) v,S,∆t in the second equation by using the first one yields e (n+1/2) v,S,∆t = e (n−1/2) v,S,∆t − (∆t) A S,p e (n) u,S,∆t + (∆t) ∆ (n+1/2) 1 , e (n+1) u,S,∆t = (∆t) e (n−1/2) v,S,∆t + e (n) u,S,∆t − (∆t) 2 A S,p eWe rewrite it in operator form by using the operator S as in(30) …”