1980
DOI: 10.1016/0304-3975(80)90007-9
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Evaluation and comparison of two efficient probabilistic primality testing algorithms

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Cited by 76 publications
(55 citation statements)
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“…Write n − 1 = 2 k q with q odd; and p i − 1 = 2 ki q i with q i odd for 1 ≤ i ≤ s, ordering the p i s such that k 1 ≤ · · · ≤ k s . Monier [8] proved that SB(n) = 1 + 2 k1s − 1 2 s − 1 s i=1 gcd(q, q i ).…”
Section: Discussionmentioning
confidence: 99%
See 1 more Smart Citation
“…Write n − 1 = 2 k q with q odd; and p i − 1 = 2 ki q i with q i odd for 1 ≤ i ≤ s, ordering the p i s such that k 1 ≤ · · · ≤ k s . Monier [8] proved that SB(n) = 1 + 2 k1s − 1 2 s − 1 s i=1 gcd(q, q i ).…”
Section: Discussionmentioning
confidence: 99%
“…Monier [8] and Rabin [13] proved that if n is an odd composite positive integer, then SB(n) ≤ (n−1)/4. In fact, as pointed by Damgård, Landrock and Pomerance [4], if n = 9 is odd and composite, then SB(n) ≤ ϕ(n)/4, i.e., P R (n) ≤ 1/4.…”
Section: Introductionmentioning
confidence: 99%
“…Rabin [11] and Monier [9] independently showed that (M, A 2 ) has probability of failure less than 1 4 . Example 2.5.…”
Section: Definition 21 ([5]) Let a ⊆ N An Elementary Probabilisticmentioning
confidence: 99%
“…However, we will allow m to assume nonintegral values. Since α(n) ≤ 1/4 for odd composite n = 9 (see [4] or [5]) and since α(9) = 1/3, we will have C m = ∅ for 0 < m ≤ ln 3/ ln 2 and C m = {9} for ln 3/ ln 2 < m ≤ 2.…”
Section: Estimatesmentioning
confidence: 99%
“…If n is prime, then S(n) = n − 1, and if n is an odd composite number, then S(n)/(n − 1) ≤ 1/4 (see Monier [4], Rabin [5]). Now if for a given n we can find an integer a ∈ [1, n − 1] such that a / ∈ S(n), then we know that n is composite.…”
Section: Introductionmentioning
confidence: 99%