2021
DOI: 10.1016/j.jmaa.2020.124713
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Existence and nonexistence of nontrivial solutions for critical biharmonic equations

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Cited by 7 publications
(2 citation statements)
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“…For problem () with the term b=0$$ b=0 $$ and V0=Vfalse(xfalse)$$ {V}_0=V(x) $$, Sun et al 15 investigated a class of nonlinear biharmonic problem with p$$ p $$‐Laplacian under some hypotheses on Vfalse(xfalse)$$ V(x) $$ and ffalse(x,vfalse)$$ f\left(x,v\right) $$, and they derive the existence and multiplicity of nontrivial solutions by variational methods and Gagliardo–Nirenberg inequality. He and Lv 16 considered problem () with Vfalse(xfalse)=λ,b=0$$ V(x)=\lambda, b=0 $$ and ffalse(ufalse)=false|ufalse|22u$$ f(u)={\left|u\right|}^{2^{\ast \ast }-2}u $$; they proved the existence and nonexistence of nontrivial solutions to problem (). In their study, 17 Song and Shi dealt with problem () in bounded domains; the existence and multiplicity of solutions are derived by employing the concentration‐compactness principle and variational method.…”
Section: Introductionmentioning
confidence: 99%
“…For problem () with the term b=0$$ b=0 $$ and V0=Vfalse(xfalse)$$ {V}_0=V(x) $$, Sun et al 15 investigated a class of nonlinear biharmonic problem with p$$ p $$‐Laplacian under some hypotheses on Vfalse(xfalse)$$ V(x) $$ and ffalse(x,vfalse)$$ f\left(x,v\right) $$, and they derive the existence and multiplicity of nontrivial solutions by variational methods and Gagliardo–Nirenberg inequality. He and Lv 16 considered problem () with Vfalse(xfalse)=λ,b=0$$ V(x)=\lambda, b=0 $$ and ffalse(ufalse)=false|ufalse|22u$$ f(u)={\left|u\right|}^{2^{\ast \ast }-2}u $$; they proved the existence and nonexistence of nontrivial solutions to problem (). In their study, 17 Song and Shi dealt with problem () in bounded domains; the existence and multiplicity of solutions are derived by employing the concentration‐compactness principle and variational method.…”
Section: Introductionmentioning
confidence: 99%
“…7), we haveo(1) = J ′ ψ (u n ), u n − u = Ω |∆u n | 2 dx − Ω ∆u n ∆udx + ψ 0 ( Ω |∇u n | 2 dx) Ω ∇u n ∇(u n − u)dx − λ Ω f (x, u n )(u n − u)dx − Ω |u n | 2 * * −2 u n (u n − u)dx.…”
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