2000
DOI: 10.1007/s11661-006-0248-y
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Experimental investigation and thermodynamic modeling of the Cr-Ni-Si system

Abstract: The constitution of the Cr-Ni-Si ternary system is established via experiment and thermodynamic modeling. In the experimental section, 35 decisive alloys, the compositions of which are based on a preliminary calculation using available literature data, are prepared by arc melting of cold-pressed pellets and annealing at 900 ЊC for 25 days. Water-quenched samples are analyzed by using X-ray diffraction (XRD) and differential thermal analysis (DTA) techniques. In the modeling section, a consistent thermodynamic … Show more

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Cited by 38 publications
(16 citation statements)
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“…Schuster and Du [6] extensively studied the Ni-Si-Cr phase diagram, providing data for CALPHAD modeling. Lebrun et al [7] recently reviewed experimental and modeling data on the Ni-Si-B system.…”
Section: Introductionmentioning
confidence: 99%
“…Schuster and Du [6] extensively studied the Ni-Si-Cr phase diagram, providing data for CALPHAD modeling. Lebrun et al [7] recently reviewed experimental and modeling data on the Ni-Si-B system.…”
Section: Introductionmentioning
confidence: 99%
“…A thermodynamic model for the Cr‐Si‐Ti system is needed within our research program [1–6] aiming at establishing the phase diagrams of the C‐Cr‐Ni‐Si‐Ti quinary system and its constituent ternaries and quaternaries using both experimental and thermodynamic methods and calculation. Information about the phase equilibria and thermodynamic properties in the C‐Cr‐Ni‐Si‐Ti system is of fundamental importance in many applications, such as the joining of SiC with Ti modified Cr‐Ni brazes [7], ohmic contacts in integrated circuits [8], and self‐propagating high‐temperature synthesis [9].…”
mentioning
confidence: 99%
“…A thermodynamic assessment of the Ni-Si system by Du and Schuster [53,54] is adopted to obtain the thermodynamic properties of c, d and L (e.g., g r , g d , l AÃ L , l BÃ L , l AL , and l BL ) and the equilibrium eutectic point (T eq E ¼ 1513:2 (K), C eq E ¼ 0:2965 (atom fraction)). Since both c and d are treated as SCs [53,54], the volume fractions of c and d are both constants independent on V, e.g., if C 1 is set to be 0.298, f c ¼ 0:742 and f d ¼ 0:258 are obtained from Eq. (25) by noting that C c ¼ 2=7 and C d ¼ 1=3.…”
Section: Simulation Resultsmentioning
confidence: 99%